-.01x^2+.6x+6.2=0

Solution for -.01x^2+.6x+6.2=0 equation:

-.01x^2+.6x+6.2=0

We add all the numbers together, and all the variables

-0.01x^2+.6x+6.2=0

a = -0.01; b = .6; c = +6.2;
Δ = b2-4ac
Δ = .62-4·(-0.01)·6.2
Δ = 0.608
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(.6)-\sqrt{0.608}}{2*-0.01}=\frac{-0.6-\sqrt{0.608}}{-0.02}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(.6)+\sqrt{0.608}}{2*-0.01}=\frac{-0.6+\sqrt{0.608}}{-0.02}
$